To find the new volume of gas when the pressure changes, we can use Boyle's Law, which states that:
\[ P_1 V_1 = P_2 V_2 \]
Where:
- \( P_1 \) is the initial pressure
- \( V_1 \) is the initial volume
- \( P_2 \) is the final pressure
- \( V_2 \) is the final volume
Given:
- \( P_1 = 1.1 , \text{atm} \)
- \( V_1 = 0.326 , \text{L} \)
- \( P_2 = 1.9 , \text{atm} \)
We need to find \( V_2 \). Rearranging the formula gives:
\[ V_2 = \frac{P_1 V_1}{P_2} \]
Substituting the known values:
\[ V_2 = \frac{(1.1 , \text{atm}) \times (0.326 , \text{L})}{1.9 , \text{atm}} \]
Calculating it step-by-step:
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Calculate the numerator: \[ 1.1 \times 0.326 = 0.3596 \]
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Now divide by the final pressure: \[ V_2 = \frac{0.3596}{1.9} \approx 0.1893 , \text{L} \]
Rounding to three significant figures gives approximately \( 0.189 , \text{L} \).
Thus, the correct answer is:
d) 0.189 L