Question

A volume of gas at 1.1atm was measured at 0.326 L. What will the volume be when changed to 1.9atm?

a
0.164 L
b
0.223 L
c
0.143 L
d
0.189 L

Answer 1

To find the new volume of gas when the pressure changes, we can use Boyle's Law, which states that:

\[ P_1 V_1 = P_2 V_2 \]

Where:
- \( P_1 \) is the initial pressure
- \( V_1 \) is the initial volume
- \( P_2 \) is the final pressure
- \( V_2 \) is the final volume

Given:
- \( P_1 = 1.1 \, \text{atm} \)
- \( V_1 = 0.326 \, \text{L} \)
- \( P_2 = 1.9 \, \text{atm} \)

We need to find \( V_2 \). Rearranging the formula gives:

\[ V_2 = \frac{P_1 V_1}{P_2} \]

Substituting the known values:

\[ V_2 = \frac{(1.1 \, \text{atm}) \times (0.326 \, \text{L})}{1.9 \, \text{atm}} \]

Calculating it step-by-step:

1. Calculate the numerator:
\[ 1.1 \times 0.326 = 0.3596 \]

2. Now divide by the final pressure:
\[ V_2 = \frac{0.3596}{1.9} \approx 0.1893 \, \text{L} \]

Rounding to three significant figures gives approximately \( 0.189 \, \text{L} \).

Thus, the correct answer is:

**d) 0.189 L**