To determine the volume of a gas at a different temperature while the pressure is held constant, you can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when pressure is constant. The formula is:
\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]
Where:
- \( V_1 \) is the initial volume (1.0 L)
- \( T_1 \) is the initial temperature (298 K)
- \( V_2 \) is the final volume (unknown)
- \( T_2 \) is the final temperature (373 K)
Rearranging the formula to solve for \( V_2 \):
\[ V_2 = V_1 \times \frac{T_2}{T_1} \]
Substituting in the values:
\[ V_2 = 1.0 , \text{L} \times \frac{373 , \text{K}}{298 , \text{K}} \]
Calculating the right side:
\[ V_2 = 1.0 , \text{L} \times 1.252 = 1.252 , \text{L} \]
Thus, the gas will occupy approximately 1.25 L.
None of the given answer choices match this closely, but the value is closest to option d (1.3 L).