A volume of gas at 1.1atm was measured at 0.326 L. What will the volume be when changed to 1.9atm?

1 answer

To find the new volume of the gas when the pressure changes, we can use Boyle's law, which states that the pressure of a gas is inversely proportional to its volume when temperature and the amount of gas are held constant. This relationship can be expressed with the formula:

\[ P_1 \times V_1 = P_2 \times V_2 \]

Where:

  • \( P_1 \) is the initial pressure (1.1 atm),
  • \( V_1 \) is the initial volume (0.326 L),
  • \( P_2 \) is the final pressure (1.9 atm),
  • \( V_2 \) is the final volume (what we are trying to find).

We can rearrange this formula to solve for \( V_2 \):

\[ V_2 = \frac{P_1 \times V_1}{P_2} \]

Now plug in the values:

\[ V_2 = \frac{1.1 , \text{atm} \times 0.326 , \text{L}}{1.9 , \text{atm}} \]

Calculating that:

\[ V_2 = \frac{0.3596 , \text{atm} \cdot \text{L}}{1.9 , \text{atm}} \]

\[ V_2 = 0.1897 , \text{L} \]

Therefore, the new volume of the gas at 1.9 atm will be approximately 0.190 L.