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Solve for x to determine the equation has one, none, or infinite solutions.
3(2x + 2) - 4 = -2x + 10
A. The equation has one solution: x = 0.
B. The equation has no solution.
C. The equation has one solution: x = 1.
D. The equation has infinite solutions.
3(2x + 2) - 4 = -2x + 10
A. The equation has one solution: x = 0.
B. The equation has no solution.
C. The equation has one solution: x = 1.
D. The equation has infinite solutions.
Answers
Answered by
GPT-4o mini
To solve the equation \( 3(2x + 2) - 4 = -2x + 10 \), we will first simplify each side of the equation step by step.
1. Distribute on the left side:
\[
3(2x + 2) = 6x + 6
\]
So, the left side becomes:
\[
6x + 6 - 4 = 6x + 2
\]
Therefore, the equation simplifies to:
\[
6x + 2 = -2x + 10
\]
2. Next, we will add \( 2x \) to both sides to get all \( x \) terms on one side:
\[
6x + 2 + 2x = 10
\]
Which simplifies to:
\[
8x + 2 = 10
\]
3. Now, subtract \( 2 \) from both sides:
\[
8x = 8
\]
4. Finally, divide by \( 8 \):
\[
x = 1
\]
Now, let's determine the nature of the solution. Since we found that \( x = 1 \) is the only solution, we conclude that:
**The equation has one solution: \( x = 1 \).**
Therefore, the correct answer is:
**C. The equation has one solution: x = 1.**
1. Distribute on the left side:
\[
3(2x + 2) = 6x + 6
\]
So, the left side becomes:
\[
6x + 6 - 4 = 6x + 2
\]
Therefore, the equation simplifies to:
\[
6x + 2 = -2x + 10
\]
2. Next, we will add \( 2x \) to both sides to get all \( x \) terms on one side:
\[
6x + 2 + 2x = 10
\]
Which simplifies to:
\[
8x + 2 = 10
\]
3. Now, subtract \( 2 \) from both sides:
\[
8x = 8
\]
4. Finally, divide by \( 8 \):
\[
x = 1
\]
Now, let's determine the nature of the solution. Since we found that \( x = 1 \) is the only solution, we conclude that:
**The equation has one solution: \( x = 1 \).**
Therefore, the correct answer is:
**C. The equation has one solution: x = 1.**
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