Asked by I_EAT_EVERYDAY
1. Which equation has the same solution for x as this equation: x − 12 = 40?
A). 12 − x = 40
B). x over 2 = 14
C). x over 4 = 13
D). x +12 = −40
A). 12 − x = 40
B). x over 2 = 14
C). x over 4 = 13
D). x +12 = −40
Answers
Answered by
I_EAT_EVERYDAY
An expression for the length of the rectangle in terms of the width would be
Answered by
GPT-4o mini
To find which equation has the same solution for \( x \) as the equation \( x - 12 = 40 \), we first need to solve the original equation:
\[
x - 12 = 40
\]
Adding 12 to both sides gives:
\[
x = 40 + 12
\]
\[
x = 52
\]
Now we can check each option to see if it also results in \( x = 52 \):
A) \( 12 - x = 40 \)
Subtracting 12 from both sides:
\[
-x = 40 - 12
\]
\[
-x = 28
\]
Multiplying by -1:
\[
x = -28 \quad (\text{Not the same solution})
\]
B) \( \frac{x}{2} = 14 \)
Multiplying both sides by 2 gives:
\[
x = 14 \times 2
\]
\[
x = 28 \quad (\text{Not the same solution})
\]
C) \( \frac{x}{4} = 13 \)
Multiplying both sides by 4 gives:
\[
x = 13 \times 4
\]
\[
x = 52 \quad (\text{This is the same solution})
\]
D) \( x + 12 = -40 \)
Subtracting 12 from both sides gives:
\[
x = -40 - 12
\]
\[
x = -52 \quad (\text{Not the same solution})
\]
The equation that has the same solution for \( x \) as \( x - 12 = 40 \) is:
**C) \( \frac{x}{4} = 13 \)**.
\[
x - 12 = 40
\]
Adding 12 to both sides gives:
\[
x = 40 + 12
\]
\[
x = 52
\]
Now we can check each option to see if it also results in \( x = 52 \):
A) \( 12 - x = 40 \)
Subtracting 12 from both sides:
\[
-x = 40 - 12
\]
\[
-x = 28
\]
Multiplying by -1:
\[
x = -28 \quad (\text{Not the same solution})
\]
B) \( \frac{x}{2} = 14 \)
Multiplying both sides by 2 gives:
\[
x = 14 \times 2
\]
\[
x = 28 \quad (\text{Not the same solution})
\]
C) \( \frac{x}{4} = 13 \)
Multiplying both sides by 4 gives:
\[
x = 13 \times 4
\]
\[
x = 52 \quad (\text{This is the same solution})
\]
D) \( x + 12 = -40 \)
Subtracting 12 from both sides gives:
\[
x = -40 - 12
\]
\[
x = -52 \quad (\text{Not the same solution})
\]
The equation that has the same solution for \( x \) as \( x - 12 = 40 \) is:
**C) \( \frac{x}{4} = 13 \)**.
Answered by
GPT-4o mini
To express the length of a rectangle in terms of its width, we typically need to have some relationship between the length and the width.
Let's denote:
- \( L \) as the length of the rectangle
- \( W \) as the width of the rectangle
A common relationship used is the area of the rectangle. If you know the area \( A \) of the rectangle, the formula for the area is given by:
\[
A = L \times W
\]
From this, you can solve for the length \( L \) in terms of the width \( W \):
\[
L = \frac{A}{W}
\]
If the problem provides a specific relationship or a different equation that relates length and width (like a perimeter constraint or ratio), please provide that, and we can derive the expression based on that relationship. Otherwise, the formula above is a standard way to express the length in terms of the width when the area is known.
Let's denote:
- \( L \) as the length of the rectangle
- \( W \) as the width of the rectangle
A common relationship used is the area of the rectangle. If you know the area \( A \) of the rectangle, the formula for the area is given by:
\[
A = L \times W
\]
From this, you can solve for the length \( L \) in terms of the width \( W \):
\[
L = \frac{A}{W}
\]
If the problem provides a specific relationship or a different equation that relates length and width (like a perimeter constraint or ratio), please provide that, and we can derive the expression based on that relationship. Otherwise, the formula above is a standard way to express the length in terms of the width when the area is known.
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