Question
Simplify the polynomial expression (xy - 2)(2^2 + 1). to make a answer use the boxes
_x^3y+_x^2+_xy+_
_x^3y+_x^2+_xy+_
Answers
Answered by
GPT-4o mini
To simplify the polynomial expression \((xy - 2)(2^2 + 1)\), we start by evaluating the expression in parentheses:
\[
2^2 + 1 = 4 + 1 = 5
\]
Now, substitute this back into the expression:
\[
(xy - 2)(5)
\]
Next, distribute the \(5\) across the terms inside the parentheses:
\[
5(xy - 2) = 5xy - 10
\]
Now, rewrite this in the form requested, which is \(_x^3y + _x^2 + _xy + _\).
Since there are no terms with \(x^3\), \(x^2\), or \(xy\) besides those already produced, we can fill in the boxes as follows:
- Coefficient of \(x^3y\): \(0\)
- Coefficient of \(x^2\): \(0\)
- Coefficient of \(xy\): \(5\)
- Constant term: \(-10\)
Thus, the fully simplified polynomial expression is:
\[
\boxed{0} \quad \boxed{0} \quad \boxed{5} \quad \boxed{-10}
\]
\[
2^2 + 1 = 4 + 1 = 5
\]
Now, substitute this back into the expression:
\[
(xy - 2)(5)
\]
Next, distribute the \(5\) across the terms inside the parentheses:
\[
5(xy - 2) = 5xy - 10
\]
Now, rewrite this in the form requested, which is \(_x^3y + _x^2 + _xy + _\).
Since there are no terms with \(x^3\), \(x^2\), or \(xy\) besides those already produced, we can fill in the boxes as follows:
- Coefficient of \(x^3y\): \(0\)
- Coefficient of \(x^2\): \(0\)
- Coefficient of \(xy\): \(5\)
- Constant term: \(-10\)
Thus, the fully simplified polynomial expression is:
\[
\boxed{0} \quad \boxed{0} \quad \boxed{5} \quad \boxed{-10}
\]
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