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Show a complete algebraic solution for the following: find 4 consecutive multiples of 11 with the sum of 2178
15 years ago

Answers

Damon
n-1 + n + n+1 + n+2 = 2178

4 n + 2 = 2178

4 n = 2176

n = 544
n-1 = 543
so
543,544,etc
15 years ago

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