Question
A table of values is representing a linear relationship is shown.
x
-2
0
2
4
y
-7
-3
1
5
Which equation models this relationship in slope-intercept form?
(1 point)
Responses
y=2x−3
y is equal to 2 x minus 3
y=−2x−3
y is equal to negative 2 x minus 3
y=12x−3
y is equal to 1 half x minus 3
y=−4x−3
y is equal to negative 4 x minus 3
y=3x−3
y is equal to 3 x minus 3
y=2x−7
y is equal to 2 x minus 7
y=2x−5
y is equal to 2 x minus 5
y=−2x−1
y is equal to negative 2 x minus 1
y=12x−7
x
-2
0
2
4
y
-7
-3
1
5
Which equation models this relationship in slope-intercept form?
(1 point)
Responses
y=2x−3
y is equal to 2 x minus 3
y=−2x−3
y is equal to negative 2 x minus 3
y=12x−3
y is equal to 1 half x minus 3
y=−4x−3
y is equal to negative 4 x minus 3
y=3x−3
y is equal to 3 x minus 3
y=2x−7
y is equal to 2 x minus 7
y=2x−5
y is equal to 2 x minus 5
y=−2x−1
y is equal to negative 2 x minus 1
y=12x−7
Answers
GPT-4o mini
To find the equation that models the linear relationship presented by the given table of values, we need to calculate the slope (m) and the y-intercept (b) of the line in slope-intercept form, which is expressed as \( y = mx + b \).
From the table:
\[
\begin{array}{c|c}
x & y \\
\hline
-2 & -7 \\
0 & -3 \\
2 & 1 \\
4 & 5 \\
\end{array}
\]
We can calculate the slope \( m \) using any two points from the table. Let's take the points \( (0, -3) \) and \( (2, 1) \):
\[
m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - (-3)}{2 - 0} = \frac{4}{2} = 2
\]
Now, using the slope \( m = 2 \) and the point \( (0, -3) \) (where \( x = 0 \) gives us the y-intercept \( b \)), we can express the equation as:
\[
y = 2x + b
\]
Since when \( x = 0 \), \( y = -3 \):
\[
-3 = 2(0) + b \implies b = -3
\]
Thus, the equation in slope-intercept form is:
\[
y = 2x - 3
\]
The correct response is:
**y = 2x - 3**
From the table:
\[
\begin{array}{c|c}
x & y \\
\hline
-2 & -7 \\
0 & -3 \\
2 & 1 \\
4 & 5 \\
\end{array}
\]
We can calculate the slope \( m \) using any two points from the table. Let's take the points \( (0, -3) \) and \( (2, 1) \):
\[
m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - (-3)}{2 - 0} = \frac{4}{2} = 2
\]
Now, using the slope \( m = 2 \) and the point \( (0, -3) \) (where \( x = 0 \) gives us the y-intercept \( b \)), we can express the equation as:
\[
y = 2x + b
\]
Since when \( x = 0 \), \( y = -3 \):
\[
-3 = 2(0) + b \implies b = -3
\]
Thus, the equation in slope-intercept form is:
\[
y = 2x - 3
\]
The correct response is:
**y = 2x - 3**