Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Simplify 1287÷1225 .Question
Simplify 1287÷1225
.
.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To simplify \( \frac{1287}{1225} \), we can start by finding the greatest common divisor (GCD) of the two numbers.
First, let's factor both numbers:
1. For 1287:
- Dividing by 3: \( 1287 \div 3 = 429 \)
- Dividing 429 by 3 again: \( 429 \div 3 = 143 \)
- Now factor 143: \( 143 = 11 \times 13 \) (since 11 and 13 are prime)
So, the prime factorization of 1287 is:
\[
1287 = 3^2 \times 11 \times 13
\]
2. For 1225:
- Dividing by 5: \( 1225 \div 5 = 245 \)
- Dividing 245 by 5 again: \( 245 \div 5 = 49 \)
- We know that \( 49 = 7^2 \)
So, the prime factorization of 1225 is:
\[
1225 = 5^2 \times 7^2
\]
Now we check if there are any common factors:
- The factors of 1287 are \( 3^2, 11, 13 \)
- The factors of 1225 are \( 5^2, 7^2 \)
Since there are no common prime factors, the GCD is 1.
This means \( \frac{1287}{1225} \) is already in its simplest form.
Thus, the simplified form is:
\[
\frac{1287}{1225}
\]
First, let's factor both numbers:
1. For 1287:
- Dividing by 3: \( 1287 \div 3 = 429 \)
- Dividing 429 by 3 again: \( 429 \div 3 = 143 \)
- Now factor 143: \( 143 = 11 \times 13 \) (since 11 and 13 are prime)
So, the prime factorization of 1287 is:
\[
1287 = 3^2 \times 11 \times 13
\]
2. For 1225:
- Dividing by 5: \( 1225 \div 5 = 245 \)
- Dividing 245 by 5 again: \( 245 \div 5 = 49 \)
- We know that \( 49 = 7^2 \)
So, the prime factorization of 1225 is:
\[
1225 = 5^2 \times 7^2
\]
Now we check if there are any common factors:
- The factors of 1287 are \( 3^2, 11, 13 \)
- The factors of 1225 are \( 5^2, 7^2 \)
Since there are no common prime factors, the GCD is 1.
This means \( \frac{1287}{1225} \) is already in its simplest form.
Thus, the simplified form is:
\[
\frac{1287}{1225}
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.