Add the polynomial expressions 2r2−3r+4

Question

and −2r2+3r+6
.(1 point)

Answer 1

To add the polynomial expressions \( 2r^2 - 3r + 4 \) and \( -2r^2 + 3r + 6 \), you combine like terms.

Here are the two expressions:

1. \( 2r^2 - 3r + 4 \)
2. \( -2r^2 + 3r + 6 \)

Now, add the coefficients of like terms together:

• For \( r^2 \) terms: \( 2r^2 + (-2r^2) = 0r^2 \)
• For \( r \) terms: \( -3r + 3r = 0r \)
• For the constant terms: \( 4 + 6 = 10 \)

Putting it all together, we have:

\[ 0r^2 + 0r + 10 = 10 \]

So, the result of adding the two polynomial expressions is \( 10 \).