To determine which of the given equations has no solution, we need to analyze each equation:
-
Equation 1: \(3x + 4 = 3x + 3\)
Subtracting \(3x\) from both sides gives: \[ 4 = 3 \] This is false. Therefore, this equation has no solution.
-
Equation 2: \(3x + 4 = 3x + 4\)
Subtracting \(3x + 4\) from both sides gives: \[ 0 = 0 \] This is true for all \(x\). Therefore, this equation has infinitely many solutions.
-
Equation 3: \(3x + 4 = 4x + 3\)
Rearranging gives: \[ 3x + 4 - 4x = 3 \implies -x + 4 = 3 \implies -x = -1 \implies x = 1 \] This has one solution (x = 1).
-
Equation 4: \(4x + 3 = 3x + 3\)
Rearranging gives: \[ 4x - 3x + 3 = 3 \implies x + 3 = 3 \implies x = 0 \] This also has one solution (x = 0).
Based on the analysis, the equation with no solution is:
\(3x + 4 = 3x + 3\).