Which of the following is equivalent to −3i(4i+5i)%0D%0A−%0D%0A3%0D%0A𝑖%0D%0A(%0D%0A4%0D%0A𝑖%0D%0A+%0D%0A5%0D%0A𝑖%0D%0A)%0D%0A ?(1 point)%0D%0AResponses%0D%0A%0D%0A12+15i%0D%0A12%0D%0A+%0D%0A15%0D%0A𝑖%0D%0A12 plus 15 i%0D%0A%0D%0A27%0D%0A27%0D%0A27%0D%0A%0D%0A27i%0D%0A27%0D%0A𝑖%0D%0A27 i%0D%0A%0D%0A−27

1 answer

To simplify \( -3i(4i + 5i) \), we start by combining the terms inside the parentheses:

\[ 4i + 5i = 9i \]

Now, substituting this back into the expression, we have:

\[ -3i(9i) \]

Next, we can multiply these two terms:

\[ -3i \cdot 9i = -27i^2 \]

Recall that \( i^2 = -1 \). Thus:

\[ -27i^2 = -27(-1) = 27 \]

So the expression simplifies to:

\[ 27 \]

Therefore, the answer is \( \boxed{27} \).