Use the polynomial identity x2−a2=(x+a)(x−a) to rewrite x2−196 . Which polynomial does this establish?(1 point)

Answer 1

To rewrite $x^2-196$ using the polynomial identity $x^2-a^2=(x+a)(x-a)$, we can recognize that $196$ is a perfect square. Specifically, we have:

$$196={14}^2.$$

Using the identity with $a=14$, we can rewrite $x^2-196$ as follows:

$$x^2-196=x^2-{14}^2=(x+14)(x-14).$$

Thus, the polynomial $x^2-196$ is established as:

$$(x+14)(x-14).$$