To find an equation that has the same solution for \( x \) as the equation \( x - 12 = 40 \), we can solve the original equation first:
- Start with the equation \( x - 12 = 40 \).
- Add 12 to both sides to isolate \( x \): \[ x = 40 + 12 \]
- Simplifying gives: \[ x = 52 \]
Now, let's analyze each of the given equations to see if any yield \( x = 52 \):
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\( x + 12 = -40 \): \[ x = -40 - 12 = -52 \quad (\text{not the same solution}) \]
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\( \frac{x}{4} = 13 \): \[ x = 13 \times 4 = 52 \quad (\text{same solution}) \]
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\( \frac{x}{2} = 14 \): \[ x = 14 \times 2 = 28 \quad (\text{not the same solution}) \]
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\( 12 - x = 40 \): \[ -x = 40 - 12 \implies -x = 28 \implies x = -28 \quad (\text{not the same solution}) \]
The equation that has the same solution for \( x = 52 \) is:
\( \frac{x}{4} = 13 \).