To find the value of \( x \) given that Raji's square and Ava's hexagon have the same perimeter, we first calculate the perimeters of both shapes.
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Perimeter of the square: The perimeter \( P \) of a square with side length \( s \) is given by the formula: \[ P_{\text{square}} = 4s \] For Raji's square with side length \( x + 5 \): \[ P_{\text{square}} = 4(x + 5) = 4x + 20 \]
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Perimeter of the hexagon: The perimeter \( P \) of a regular hexagon with side length \( s \) is given by the formula: \[ P_{\text{hexagon}} = 6s \] For Ava's hexagon with side length \( x - 1 \): \[ P_{\text{hexagon}} = 6(x - 1) = 6x - 6 \]
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Setting the perimeters equal: Since the two figures have the same perimeter, we can set the expressions for the perimeters equal to each other: \[ 4x + 20 = 6x - 6 \]
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Solving for \( x \): Now, we can solve this equation for \( x \).
\[ 4x + 20 = 6x - 6 \] Subtract \( 4x \) from both sides: \[ 20 = 2x - 6 \] Add 6 to both sides: \[ 26 = 2x \] Divide both sides by 2: \[ x = 13 \]
Thus, the value of \( x \) is 13.