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Conservation in Chemical Reactions Quick Check 3 of 43 of 4 Items Question Use the equation and the table to answer the questio...Asked by hehehhaha
Conservation in Chemical Reactions Quick Check
3 of 4 3 of 4 Items
Question
Use the equation and the table to answer the question.
FeCl3 + 3H2O → Fe(OH)3 + 3HCl
Element Mass of an Atom (amu)
Fe 56
Cl 35
H 1
O 16
Iron chloride and water react according to the equation shown. The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?
(1 point)
Responses
108 amu
108 amu
161 amu
161 amu
215 amu
215 amu
179 amu
3 of 4 3 of 4 Items
Question
Use the equation and the table to answer the question.
FeCl3 + 3H2O → Fe(OH)3 + 3HCl
Element Mass of an Atom (amu)
Fe 56
Cl 35
H 1
O 16
Iron chloride and water react according to the equation shown. The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?
(1 point)
Responses
108 amu
108 amu
161 amu
161 amu
215 amu
215 amu
179 amu
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the total mass of the reactants in the equation \( \text{FeCl}_3 + 3\text{H}_2\text{O} \), we need to calculate the total mass of each reactant:
1. **For \(\text{FeCl}_3\)**:
- 1 atom of Fe = 56 amu
- 3 atoms of Cl = 3 × 35 amu = 105 amu
- Total mass of \(\text{FeCl}_3\) = 56 amu + 105 amu = 161 amu
2. **For \(3\text{H}_2\text{O}\)**:
- 2 atoms of H in one water molecule = 2 × 1 amu = 2 amu
- 1 atom of O in one water molecule = 16 amu
- Total mass of one water molecule = 2 amu + 16 amu = 18 amu
- For 3 water molecules: \(3 × 18 \text{ amu} = 54 \text{ amu}\)
Now, we can add the total masses of both reactants:
- Total mass of reactants = Mass of \(\text{FeCl}_3\) + Mass of \(3\text{H}_2\text{O}\) = 161 amu + 54 amu = 215 amu
Therefore, the total mass of the reactants is **215 amu**.
1. **For \(\text{FeCl}_3\)**:
- 1 atom of Fe = 56 amu
- 3 atoms of Cl = 3 × 35 amu = 105 amu
- Total mass of \(\text{FeCl}_3\) = 56 amu + 105 amu = 161 amu
2. **For \(3\text{H}_2\text{O}\)**:
- 2 atoms of H in one water molecule = 2 × 1 amu = 2 amu
- 1 atom of O in one water molecule = 16 amu
- Total mass of one water molecule = 2 amu + 16 amu = 18 amu
- For 3 water molecules: \(3 × 18 \text{ amu} = 54 \text{ amu}\)
Now, we can add the total masses of both reactants:
- Total mass of reactants = Mass of \(\text{FeCl}_3\) + Mass of \(3\text{H}_2\text{O}\) = 161 amu + 54 amu = 215 amu
Therefore, the total mass of the reactants is **215 amu**.
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