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Use the equation and the table to answer the question. FeCl3 + 3H2O → Fe(OH)3 + 3HCl Element Mass of an Atom (amu) Fe 56 Cl 35...Asked by hehehhaha
                Use the equation and the table to answer the question.
FeCl3 + 3H2O → Fe(OH)3 + 3HCl
Element Mass of an Atom (amu)
Fe 56
Cl 35
H 1
O 16
Iron chloride and water react according to the equation shown. The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?
(1 point)
Responses
108 amu
108 amu
161 amu
161 amu
215 amu
215 amu
179 amu
            
        FeCl3 + 3H2O → Fe(OH)3 + 3HCl
Element Mass of an Atom (amu)
Fe 56
Cl 35
H 1
O 16
Iron chloride and water react according to the equation shown. The table shows the atomic masses of the elements involved in the reaction. What is the total mass of the reactants?
(1 point)
Responses
108 amu
108 amu
161 amu
161 amu
215 amu
215 amu
179 amu
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To find the total mass of the reactants in the given equation, we need to calculate the mass of each reactant based on the equation:
\[
\text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl}
\]
**Step 1: Calculate the mass of FeCl₃.**
- Fe: 1 atom × 56 amu = 56 amu
- Cl: 3 atoms × 35 amu = 3 × 35 = 105 amu
Total mass of FeCl₃ = 56 amu + 105 amu = 161 amu
**Step 2: Calculate the mass of 3H₂O.**
- H: 2 atoms × 3 (for 3 water molecules) = 6 atoms; Total mass of H = 6 × 1 amu = 6 amu
- O: 1 atom × 3 (for 3 water molecules) = 3 atoms; Total mass of O = 3 × 16 amu = 48 amu
Total mass of 3H₂O = 6 amu + 48 amu = 54 amu
**Step 3: Add the masses of the reactants.**
Total mass of the reactants = Mass of FeCl₃ + Mass of 3H₂O
\[
161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu}
\]
Thus, the total mass of the reactants is **215 amu**.
**Final Answer: 215 amu**
    
\[
\text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl}
\]
**Step 1: Calculate the mass of FeCl₃.**
- Fe: 1 atom × 56 amu = 56 amu
- Cl: 3 atoms × 35 amu = 3 × 35 = 105 amu
Total mass of FeCl₃ = 56 amu + 105 amu = 161 amu
**Step 2: Calculate the mass of 3H₂O.**
- H: 2 atoms × 3 (for 3 water molecules) = 6 atoms; Total mass of H = 6 × 1 amu = 6 amu
- O: 1 atom × 3 (for 3 water molecules) = 3 atoms; Total mass of O = 3 × 16 amu = 48 amu
Total mass of 3H₂O = 6 amu + 48 amu = 54 amu
**Step 3: Add the masses of the reactants.**
Total mass of the reactants = Mass of FeCl₃ + Mass of 3H₂O
\[
161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu}
\]
Thus, the total mass of the reactants is **215 amu**.
**Final Answer: 215 amu**
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