To find the total mass of the reactants in the given equation, we need to calculate the mass of each reactant based on the equation:
\[
\text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl}
\]
**Step 1: Calculate the mass of FeCl₃.**
- Fe: 1 atom × 56 amu = 56 amu
- Cl: 3 atoms × 35 amu = 3 × 35 = 105 amu
Total mass of FeCl₃ = 56 amu + 105 amu = 161 amu
**Step 2: Calculate the mass of 3Hâ‚‚O.**
- H: 2 atoms × 3 (for 3 water molecules) = 6 atoms; Total mass of H = 6 × 1 amu = 6 amu
- O: 1 atom × 3 (for 3 water molecules) = 3 atoms; Total mass of O = 3 × 16 amu = 48 amu
Total mass of 3Hâ‚‚O = 6 amu + 48 amu = 54 amu
**Step 3: Add the masses of the reactants.**
Total mass of the reactants = Mass of FeCl₃ + Mass of 3H₂O
\[
161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu}
\]
Thus, the total mass of the reactants is **215 amu**.
**Final Answer: 215 amu**