Use the equation and the table to answer the question.

To find the total mass of the reactants in the given equation, we need to calculate the mass of each reactant based on the equation:

\[
\text{FeCl}_3 + 3\text{H}_2\text{O} \rightarrow \text{Fe(OH)}_3 + 3\text{HCl}
\]

**Step 1: Calculate the mass of FeCl₃.**

- Fe: 1 atom × 56 amu = 56 amu
- Cl: 3 atoms × 35 amu = 3 × 35 = 105 amu

Total mass of FeCl₃ = 56 amu + 105 amu = 161 amu

**Step 2: Calculate the mass of 3H₂O.**

- H: 2 atoms × 3 (for 3 water molecules) = 6 atoms; Total mass of H = 6 × 1 amu = 6 amu
- O: 1 atom × 3 (for 3 water molecules) = 3 atoms; Total mass of O = 3 × 16 amu = 48 amu

Total mass of 3H₂O = 6 amu + 48 amu = 54 amu

**Step 3: Add the masses of the reactants.**

Total mass of the reactants = Mass of FeCl₃ + Mass of 3H₂O
\[
161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu}
\]

Thus, the total mass of the reactants is **215 amu**.

**Final Answer: 215 amu**