2. Sara discarded 1/10

of the 200 apples she picked as defective. The rest were sold as fresh fruit. How many apples picked were sold as fresh fruit?(1 point)
Responses

180
180

20
20

190
190

9/10
9 tenths

7 answers

To find out how many apples were sold as fresh fruit, we first determine how many apples were discarded as defective.

Sara discarded \( \frac{1}{10} \) of the 200 apples:

\[ \text{Defective apples} = \frac{1}{10} \times 200 = 20 \]

Next, we subtract the defective apples from the total apples picked to find the amount sold as fresh fruit:

\[ \text{Fresh apples} = 200 - 20 = 180 \]

Therefore, the number of apples sold as fresh fruit is 180.

is that correct

Yes, that is correct. Here is the breakdown:

  1. Sara picked 200 apples.
  2. She discarded \( \frac{1}{10} \) of them as defective: \[ \frac{1}{10} \times 200 = 20 \text{ defective apples} \]
  3. To find the number of fresh apples, you subtract the defective apples from the total apples: \[ 200 - 20 = 180 \text{ fresh apples} \]

So, the number of apples sold as fresh fruit is indeed 180.

3. The town of Oak Manor measures 3.8 miles by 4.2 miles. Solve for the total area.

Hint: Use the formula for the area of a rectangle = length x width.

(1 point)
Responses

8 mi2
8 mi2

16 mi2
16 mi2

14.96 mi2
14.96 mi2

15.96 mi2

To find the total area of the town of Oak Manor, which is shaped like a rectangle, we can use the formula for the area of a rectangle:

\[ \text{Area} = \text{length} \times \text{width} \]

Given:

  • Length = 4.2 miles
  • Width = 3.8 miles

Now, calculate the area:

\[ \text{Area} = 4.2 , \text{miles} \times 3.8 , \text{miles} = 15.96 , \text{mi}^2 \]

Therefore, the total area is 15.96 mi².

4. A basketball player is 6 2/3
feet tall. His infant son is 1/4
as tall. How tall is his son?(1 point)
Responses

1 1/2
ft
1 and 1 half ft

2 2/3
ft
2 and 2 thirds ft

2 1/6
ft
2 and 1 sixth ft

1 2/3
ft

To find the height of the basketball player's son, who is \( \frac{1}{4} \) as tall as the player, we need to first convert the player's height from a mixed number to an improper fraction.

The basketball player's height is \( 6 \frac{2}{3} \) feet.

  1. Convert \( 6 \frac{2}{3} \) to an improper fraction: \[ 6 \frac{2}{3} = \frac{20}{3} , \text{feet} \quad (\text{since } 6 \times 3 + 2 = 20) \]

  2. Now, we find \( \frac{1}{4} \) of the player's height: \[ \text{Son's height} = \frac{1}{4} \times \frac{20}{3} = \frac{20}{12} = \frac{5}{3} , \text{feet} \]

  3. Convert \( \frac{5}{3} \) to a mixed number: \[ \frac{5}{3} = 1 \frac{2}{3} , \text{feet} \]

So, the height of the basketball player's son is 1 \( \frac{2}{3} \) feet.