Asked by Abby
A cork shoots out of a champagne bottle at an angle of 39.0 degrees above the horizontal. If the cork travels a horizontal distance of 1.10 m in 1.40 s, what was its initial speed?
Answers
Answered by
drwls
There is a formula that relates horizontal distance X to launch speed, V and angle A.
It is X = (V^2/g) sin (2 A)
See if you can derive it. In any case, use if to solve for V.
I would love to help you, and others, with more of your physics problems, but is will be necessary to show some evidence of your own work. Perhaps other teachers will help you with your other questions.
It is X = (V^2/g) sin (2 A)
See if you can derive it. In any case, use if to solve for V.
I would love to help you, and others, with more of your physics problems, but is will be necessary to show some evidence of your own work. Perhaps other teachers will help you with your other questions.
Answered by
Dave
looking for info on like question, if we do not know how to solve it and equation is greek to us, need a step through. whoever posted first obviously doesn't know how to help...
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