Asked by Abby
In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 3.9 m/s at an angle of 25 degrees above the horizontal. It is released 0.75 m above the floor.
What horizontal distance does the ball cover before bouncing?
What horizontal distance does the ball cover before bouncing?
Answers
Answered by
bobpursley
Break up the initial velocity in to horizontal and vertical components.
vertical
Vi=3.9sin25
hf=ho+vi*t-4.9t^2
0=.75+3.9sin25*t-4.9t^2 solve for time in air, t.
Then
Horizontal
distance=3.9cos25*t
vertical
Vi=3.9sin25
hf=ho+vi*t-4.9t^2
0=.75+3.9sin25*t-4.9t^2 solve for time in air, t.
Then
Horizontal
distance=3.9cos25*t
There are no AI answers yet. The ability to request AI answers is coming soon!