Solve for x

π‘₯
.
92x+3=(13)x+4
9
2
π‘₯
+
3
=
(
1
3
)
π‘₯
+
4
(1 point)
Responses
x=βˆ’2
π‘₯
=
βˆ’
2
x is equal to negative 2
x=25
π‘₯
=
2
5
x is equal to 2 fifths
x=4
π‘₯
=
4
x is equal to 4
x=3

1 answer

To solve the equation

\[ 92x + 3 = (13)x + 4 \]

we will first simplify and rearrange the equation to isolate \( x \).

  1. Start with the equation:

\[ 92x + 3 = 13^x + 4 \]

  1. Rearranging this equation gives:

\[ 92x - 13^x + 3 - 4 = 0 \]

or

\[ 92x - 13^x - 1 = 0 \]

The left-hand side (LHS) is a combination of a linear function (92x) and an exponential function (13^x). This type of equation may not have a straightforward algebraic solution, and numerical methods or graphing would typically be employed to find solutions to this kind of equation. However, we could also check the possible answers one by one to see if any satisfy the equation.

Let’s check each proposed solution:

  1. Checking \( x = -2 \):

    \[ LHS = 92(-2) + 3 = -184 + 3 = -181 \] \[ RHS = 13^{-2} + 4 = \frac{1}{169} + 4 \] Since \( \frac{1}{169} + 4 \neq -181 \), this does not satisfy.

  2. Checking \( x = \frac{2}{5} \):

    \[ LHS = 92(\frac{2}{5}) + 3 = \frac{184}{5} + 3 = \frac{184}{5} + \frac{15}{5} = \frac{199}{5} \] \[ RHS = 13^{\frac{2}{5}} + 4 \approx 2.435 + 4 \neq \frac{199}{5} \]

  3. Checking \( x = 4 \):

    \[ LHS = 92(4) + 3 = 368 + 3 = 371 \] \[ RHS = 13^4 + 4 = 28561 + 4 = 28565 \] Not equal.

  4. Checking \( x = 3 \):

    \[ LHS = 92(3) + 3 = 276 + 3 = 279 \] \[ RHS = 13^3 + 4 = 2197 + 4 = 2201 \] Not equal.

Since none of the proposed solutions seem to work, it's important to clarify that there are no exact solutions among the choices provided, given the complexity of the equation. The best method to solve this would be through numerical approximation or graphing to pinpoint the solution accurately.

If there's a simpler approach or additional context about the original problem (perhaps it's incorrectly stated), that would clarify the way forward. Otherwise, since none of these proposed solutions satisfies the equation exactly, there may be a misunderstanding in the original formulation.

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