Solve for b in the following equation: A=12(a+b) (1 point)

Question

Responses

b=2A−ab is equal to 2 cap A minus A

b=12A−ab is equal to 1 half cap A minus A

b=2A+ab is equal to 2 cap A plus A

b=12A+a

Answer 1

To solve for \( b \) in the equation \( A = 12(a + b) \), follow these steps:

1. Start with the original equation: \[ A = 12(a + b) \]

2. Divide both sides by 12: \[ \frac{A}{12} = a + b \]

3. Isolate \( b \) by subtracting \( a \) from both sides: \[ b = \frac{A}{12} - a \]

Now let's rewrite this expression for clarity: \[ b = \frac{A}{12} - a \]

Now, looking through the provided responses, we see:

• b = 2A - ab
• b = 12A - ab
• b = 2A + ab
• b = 12A + a

None of the provided options matches our solved expression \( b = \frac{A}{12} - a \).

Let's recheck if we misunderstood any of the responses:

• If \( b = \frac{A}{12} - a\), then it seems none of the options is quite fitting the simplified result based on the given variable relations.

Would you like to provide any further context or re-check the options?