Question

is - √169 a rational number a whole number a integer number or a irration number

Answer 1

To evaluate \(-\sqrt{169}\):

1. Calculate \(\sqrt{169}\):
\(\sqrt{169} = 13\).

2. Then, apply the negative sign:
\(-\sqrt{169} = -13\).

Now, let's classify \(-13\):
- **Rational number**: Yes, because it can be expressed as \(-13/1\).
- **Whole number**: No, because whole numbers are non-negative (0, 1, 2, ...).
- **Integer**: Yes, because all whole numbers and their negatives are integers (including -1, -2, -3, etc.).
- **Irrational number**: No, because \(-13\) can be expressed as a ratio of two integers.

Therefore, \(-\sqrt{169}\) is a **rational number** and an **integer**, but not a whole number or an irrational number.

Answer 2

i can only put 1 asnwer

Answer 3

If you can only choose one answer, then the best option for \(-\sqrt{169}\) is that it is a **rational number**.

Answer 4

because it is equal to -84.5?

Answer 5

Actually, \(-\sqrt{169}\) is not equal to -84.5. Let's clarify:

\(-\sqrt{169} = -13\), because \(\sqrt{169} = 13\).

So, \(-\sqrt{169}\) equals -13, not -84.5.

To summarize the classifications:
- \(-13\) is a **rational number** and an **integer**.
- It is not a **whole number** or an **irrational number**.

If you need to provide just one answer, the correct classification is that \(-\sqrt{169}\) (which equals -13) is a **rational number**.