Asked by yayy
convert 0.7 (theres a bar over 7) to a fraction.
Answers
Answered by
yayy
which of the following is an irrational number between 4 and 8?
1. square root of 12
2. square root of 5
3. square root of 8
4. square root of 17
1. square root of 12
2. square root of 5
3. square root of 8
4. square root of 17
Answered by
yayy
Which of the following rational numbers is not between the square root of 3 and the square root of 6
1. 1.8
2. the square root of 4
3. 1.5
4. 2
1. 1.8
2. the square root of 4
3. 1.5
4. 2
Answered by
GPT-4o mini
To convert the repeating decimal \(0.7\overline{7}\) to a fraction, follow these steps:
1. Let \(x = 0.7\overline{7}\).
2. To eliminate the repeating part, multiply \(x\) by 10 (which shifts the decimal point one place to the right):
\[
10x = 7.7\overline{7}
\]
3. Now, subtract the original \(x\) from this equation:
\[
10x - x = 7.7\overline{7} - 0.7\overline{7}
\]
Simplifying this gives:
\[
9x = 7
\]
4. Now, solve for \(x\):
\[
x = \frac{7}{9}
\]
Thus, \(0.7\overline{7}\) as a fraction is \(\frac{7}{9}\).
1. Let \(x = 0.7\overline{7}\).
2. To eliminate the repeating part, multiply \(x\) by 10 (which shifts the decimal point one place to the right):
\[
10x = 7.7\overline{7}
\]
3. Now, subtract the original \(x\) from this equation:
\[
10x - x = 7.7\overline{7} - 0.7\overline{7}
\]
Simplifying this gives:
\[
9x = 7
\]
4. Now, solve for \(x\):
\[
x = \frac{7}{9}
\]
Thus, \(0.7\overline{7}\) as a fraction is \(\frac{7}{9}\).
Answered by
GPT-4o mini
To determine which of the given options is an irrational number between 4 and 8, we can evaluate each one:
1. **Square root of 12**:
\[
\sqrt{12} \approx 3.46 \quad \text{(not between 4 and 8, and is irrational)}
\]
2. **Square root of 5**:
\[
\sqrt{5} \approx 2.24 \quad \text{(not between 4 and 8, and is irrational)}
\]
3. **Square root of 8**:
\[
\sqrt{8} = 2\sqrt{2} \approx 2.83 \quad \text{(not between 4 and 8, and is irrational)}
\]
4. **Square root of 17**:
\[
\sqrt{17} \approx 4.12 \quad \text{(between 4 and 8, and is irrational)}
\]
Among the options provided, **\(\sqrt{17}\)** is the only irrational number that falls within the range of 4 and 8.
1. **Square root of 12**:
\[
\sqrt{12} \approx 3.46 \quad \text{(not between 4 and 8, and is irrational)}
\]
2. **Square root of 5**:
\[
\sqrt{5} \approx 2.24 \quad \text{(not between 4 and 8, and is irrational)}
\]
3. **Square root of 8**:
\[
\sqrt{8} = 2\sqrt{2} \approx 2.83 \quad \text{(not between 4 and 8, and is irrational)}
\]
4. **Square root of 17**:
\[
\sqrt{17} \approx 4.12 \quad \text{(between 4 and 8, and is irrational)}
\]
Among the options provided, **\(\sqrt{17}\)** is the only irrational number that falls within the range of 4 and 8.
Answered by
GPT-4o mini
To determine which of the given rational numbers is not between \(\sqrt{3}\) and \(\sqrt{6}\), we first need to find approximate values for \(\sqrt{3}\) and \(\sqrt{6}\):
- **Calculate \(\sqrt{3}\)**:
\[
\sqrt{3} \approx 1.732
\]
- **Calculate \(\sqrt{6}\)**:
\[
\sqrt{6} \approx 2.449
\]
Now we can establish the interval:
- \(\sqrt{3} \approx 1.732\)
- \(\sqrt{6} \approx 2.449\)
The rational numbers we need to evaluate are:
1. **1.8**:
\[
1.732 < 1.8 < 2.449 \quad \text{(between)}
\]
2. **\(\sqrt{4}\)**:
\[
\sqrt{4} = 2 \quad \text{(between)}
\]
3. **1.5**:
\[
1.5 < 1.732 \quad \text{(not between)}
\]
4. **2**:
\[
1.732 < 2 < 2.449 \quad \text{(between)}
\]
The only number from the list that is **not** between \(\sqrt{3}\) and \(\sqrt{6}\) is **1.5**.
- **Calculate \(\sqrt{3}\)**:
\[
\sqrt{3} \approx 1.732
\]
- **Calculate \(\sqrt{6}\)**:
\[
\sqrt{6} \approx 2.449
\]
Now we can establish the interval:
- \(\sqrt{3} \approx 1.732\)
- \(\sqrt{6} \approx 2.449\)
The rational numbers we need to evaluate are:
1. **1.8**:
\[
1.732 < 1.8 < 2.449 \quad \text{(between)}
\]
2. **\(\sqrt{4}\)**:
\[
\sqrt{4} = 2 \quad \text{(between)}
\]
3. **1.5**:
\[
1.5 < 1.732 \quad \text{(not between)}
\]
4. **2**:
\[
1.732 < 2 < 2.449 \quad \text{(between)}
\]
The only number from the list that is **not** between \(\sqrt{3}\) and \(\sqrt{6}\) is **1.5**.
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