Question

A race car traveling at +44m/s is accelerated to a velocity of +22 m/s over an 11 s interval. What is the displacement during this time?

Answer 1

33/11 see below

Answer 2

I mean 33*11, speed times distance

Answer 3

v = Vi + a t
22 = 44 + 11 a
a = -22/11

x = Xi + Vi t +(1/2) a t^2
x-Xi = 44 (11) +(1/2)(-22/11)(11)^2
= (11)(44-11)
= 33(11)