Asked by Suzie

A race car traveling at +44m/s is accelerated to a velocity of +22 m/s over an 11 s interval. What is the displacement during this time?

Answers

Answered by Damon
33/11 see below
Answered by Damon
I mean 33*11, speed times distance
Answered by Damon
v = Vi + a t
22 = 44 + 11 a
a = -22/11

x = Xi + Vi t +(1/2) a t^2
x-Xi = 44 (11) +(1/2)(-22/11)(11)^2
= (11)(44-11)
= 33(11)
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