Question

our people have found the distance in kilometers across a small bridge using different methods.%0D%0ATheir results are given in the table. Order the distances from least to greatest.%0D%0A%0D%0A%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A512, 28−−√, 5.5¯¯¯, 234%0D%0A5%0D%0A1%0D%0A2%0D%0A,%0D%0A %0D%0A28%0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A23%0D%0A4%0D%0A512, 28−−√, 5.5¯¯¯, 234%0D%0A5%0D%0A1%0D%0A2%0D%0A,%0D%0A %0D%0A28%0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A23%0D%0A4%0D%0A%0D%0A28−−√, 512, 5.5¯¯¯, 234%0D%0A28%0D%0A,%0D%0A %0D%0A5%0D%0A1%0D%0A2%0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A23%0D%0A4%0D%0A28−−√, 512, 5.5¯¯¯, 234%0D%0A28%0D%0A,%0D%0A %0D%0A5%0D%0A1%0D%0A2%0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A23%0D%0A4%0D%0A%0D%0A28−−√, 5.5¯¯¯, 234, 512%0D%0A28%0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A23%0D%0A4%0D%0A,%0D%0A %0D%0A5%0D%0A1%0D%0A2%0D%0A28−−√, 5.5¯¯¯, 234, 512%0D%0A28%0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A23%0D%0A4%0D%0A,%0D%0A %0D%0A5%0D%0A1%0D%0A2%0D%0A%0D%0A234 , 5.5¯¯¯, 28−−√, 512%0D%0A23%0D%0A4%0D%0A %0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A28%0D%0A,%0D%0A %0D%0A5%0D%0A1%0D%0A2%0D%0A234 , 5.5¯¯¯, 28−−√, 512%0D%0A23%0D%0A4%0D%0A %0D%0A,%0D%0A %0D%0A5.%0D%0A5%0D%0A¯%0D%0A,%0D%0A %0D%0A28%0D%0A,%0D%0A %0D%0A5%0D%0A1%0D%0A2%0D%0ASkip to navigation

Answer 1

you sure

Answer 2

show the steps that you did to get that answer

Answer 3

dumb it down

Answer 4

dumb down how you got the answer

Answer 5

like not so many words and unnecessary symbols

Answer 6

To order the distances from least to greatest, we need to evaluate the values provided. The distances are:

1. \( 512 \)
2. \( \sqrt{28} \)
3. \( 5.5 \) (which can be written as \( 5.\overline{5} \) as well)
4. \( 234 \)

Now, let's calculate or approximate these values:

1. \( 512 \) (is already in numeric form)
2. \( \sqrt{28} \approx 5.29 \) (since \( 5.2^2 = 27.04 \) and \( 5.3^2 = 28.09 \), so it's between those two)
3. \( 5.5 \) (is already in numeric form)
4. \( 234 \) (is already in numeric form)

Now let's compare them:

- \( 5.29 \) (approx. \( \sqrt{28} \))
- \( 5.5 \)
- \( 512 \)
- \( 234 \)

Ordering these from least to greatest, we get:

1. \( \sqrt{28} \approx 5.29 \)
2. \( 5.5 \)
3. \( 234 \)
4. \( 512 \)

Thus, the distances ordered from least to greatest are:

**\( \sqrt{28}, 5.5, 234, 512 \)**.

Answer 7

Let's double-check the order of values given your distances:

1. **\( 512 \)**
2. **\( \sqrt{28} \)**
3. **\( 5.5 \)**
4. **\( 234 \)**

Now, let's calculate the approximate values more accurately:

- **\( 512 \)**: This is obviously \( 512 \).
- **\( \sqrt{28} \)**: The exact square root of \( 28 \) is approximately \( 5.2915 \) (you can calculate this more precisely using a calculator).
- **\( 5.5 \)**: This is exactly \( 5.5 \).
- **\( 234 \)**: This is obviously \( 234 \).

Now let's compare the numerical values:

1. **\( \sqrt{28} \approx 5.2915 \)**
2. **\( 5.5 = 5.5 \)**
3. **\( 234 \)**
4. **\( 512 \)**

Now we compare these to order them:

- The smallest is **\( \sqrt{28} \) (~5.2915)**
- The next is **\( 5.5 \)**
- Then we have **\( 234 \)**
- And finally, **\( 512 \)** is the largest.

So, correctly ordered from least to greatest, the distances are:

**\( \sqrt{28}, 5.5, 234, 512 \)**.

Thank you for prompting me to double-check! Let me know if you have more questions.

Answer 8

Sure! Here are the step-by-step calculations to determine the order of the distances \( \sqrt{28} \), \( 5.5 \), \( 234 \), and \( 512 \):

### Step 1: Identify the Distances
The distances given are:
- \( 512 \)
- \( \sqrt{28} \)
- \( 5.5 \)
- \( 234 \)

### Step 2: Calculate \( \sqrt{28} \)
To calculate \( \sqrt{28} \), you can estimate it:

- We know that \( 5.2^2 = 27.04 \) and \( 5.3^2 = 28.09 \).
- Since \( 28 \) falls between \( 27.04 \) and \( 28.09 \), we can conclude that:
\[
5.2 < \sqrt{28} < 5.3
\]

Using a calculator for more precision:
\[
\sqrt{28} \approx 5.2915
\]

### Step 3: List All Values
Now we have the approximate values of each distance:
- \( 512 \)
- \( \sqrt{28} \approx 5.2915 \)
- \( 5.5 \)
- \( 234 \)

### Step 4: Ordering the Values
Next, we need to compare these values to find the order from least to greatest:

1. **Comparing \( \sqrt{28} \) and \( 5.5 \)**:
- \( 5.2915 < 5.5 \)
- So \( \sqrt{28} \) is the smallest so far.

2. **Comparing \( 234 \)**:
- \( 234 > 5.5 \)
- So \( 5.5 < 234 \).

3. **Comparing \( 512 \)**:
- \( 512 > 234 \)
- So \( 234 < 512 \).

### Step 5: Compile the Order
Based on the above comparisons, we can order the values from least to greatest:
1. \( \sqrt{28} \) (approximately \( 5.2915 \))
2. \( 5.5 \)
3. \( 234 \)
4. \( 512 \)

### Final Ordered List
Thus, the distances in order from least to greatest are:

**\( \sqrt{28}, 5.5, 234, 512 \)**.

Let me know if you have any other questions or if there’s anything else I can assist you with!

Answer 9

Sure! Let’s make it super simple. Here’s how we find the order of the distances step-by-step:

### Step 1: Write Down the Distances
We have these distances to compare:
- \( 512 \)
- \( \sqrt{28} \)
- \( 5.5 \)
- \( 234 \)

### Step 2: Find the Value of \( \sqrt{28} \)
- We want to estimate \( \sqrt{28} \), which is the same as asking, "What number times itself equals 28?"
- We can guess that it’s between \( 5.2 \) and \( 5.3 \).
- \( 5.2 \times 5.2 = 27.04 \) (less than 28)
- \( 5.3 \times 5.3 = 28.09 \) (more than 28)
- So, \( \sqrt{28} \) is about \( 5.2915 \) (you can check this with a calculator).

### Step 3: Compare All the Values
Now we have the values:
1. \( \sqrt{28} \) is about \( 5.2915 \)
2. \( 5.5 \)
3. \( 234 \)
4. \( 512 \)

Now let’s put these in order from the smallest to largest:
- \( 5.2915 \) (which is \( \sqrt{28} \)) is the smallest.
- Next is \( 5.5 \).
- Then comes \( 234 \).
- Last is \( 512 \).

### Step 4: Write the Final Order
So, if we list them from least to greatest, we get:

1. \( \sqrt{28} \) (about \( 5.2915 \))
2. \( 5.5 \)
3. \( 234 \)
4. \( 512 \)

**Final Right Order:** **\( \sqrt{28}, 5.5, 234, 512 \)**

And that’s it! Let me know if you need anything else!

Answer 10

Absolutely! Here’s a very simple breakdown of how I figured out the order of the distances:

### Step 1: List the Distances
We start with these numbers:
- \( 512 \)
- \( \sqrt{28} \) (we'll find this value)
- \( 5.5 \)
- \( 234 \)

### Step 2: Understand \( \sqrt{28} \)
- **What is \( \sqrt{28} \)?** It’s a number that, when multiplied by itself, gives \( 28 \).
- You can guess that it’s a bit more than \( 5.2 \) (because \( 5.2 \times 5.2 = 27.04 \)) but less than \( 5.3 \) (because \( 5.3 \times 5.3 = 28.09 \)).
- So, it’s like \( 5.2 < \sqrt{28} < 5.3 \).
- If you find the exact value (using a calculator), \( \sqrt{28} \approx 5.2915 \).

### Step 3: Write Down All the Numbers
Now we have:
1. \( \sqrt{28} \approx 5.2915 \)
2. \( 5.5 \)
3. \( 234 \)
4. \( 512 \)

### Step 4: Compare All the Numbers
Now, let’s compare the approximate values:
- \( \sqrt{28} \approx 5.2915 \) (this is the smallest)
- \( 5.5 \) is next (bigger than \( 5.2915 \))
- \( 234 \) is much bigger than both \( 5.2915 \) and \( 5.5 \)
- \( 512 \) is the biggest of all.

### Step 5: Put Them in Order
So, the order from smallest to biggest is:
1. \( \sqrt{28} \) (about \( 5.2915 \))
2. \( 5.5 \)
3. \( 234 \)
4. \( 512 \)

### Final Answer
So when you put it all together:
**The order is:** \( \sqrt{28}, 5.5, 234, 512 \)

And that’s how I got the answer! Let me know if you need anything else!

Answer 11

Got it! Here’s a simpler version without extra details:

**Step 1: Distances to compare**
- 512
- √28
- 5.5
- 234

**Step 2: Find √28**
- √28 is about **5.29**.

**Step 3: Compare the values**
- **5.29** (√28)
- **5.5**
- **234**
- **512**

**Step 4: Order from least to greatest**
1. √28 (about 5.29)
2. 5.5
3. 234
4. 512

**Final Answer:**
**√28, 5.5, 234, 512**

Let me know if you need more help!