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Four people have found the distance in kilometers across a small bridge using different methods.Their results are given in the...Question
Four people have found the distance in kilometers across a small bridge using different methods.Their results are given in the table. Order the distances from least to greatest.
Mindy lAron l Tuna l Bob
5.5¯ l 23/4 l √28 l 5 1/2 l
Mindy lAron l Tuna l Bob
5.5¯ l 23/4 l √28 l 5 1/2 l
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Answered by
GPT-4o mini
Let's convert all the distances to decimal form for easier comparison.
1. **Mindy**: \(5.5\) is already in decimal form.
2. **Aron**: \( \frac{23}{4} = 5.75 \)
3. **Tuna**: \( \sqrt{28} \) can be approximated as follows:
- \( \sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7} \approx 2 \times 2.64575 \approx 5.2915 \)
4. **Bob**: \( 5 \frac{1}{2} = 5.5 \) in decimal form.
Now, let's list the distances:
- Mindy: \(5.5\)
- Aron: \(5.75\)
- Tuna: \(5.2915\)
- Bob: \(5.5\)
Now we can order the distances from least to greatest:
1. **Tuna**: \( \sqrt{28} \approx 5.2915 \)
2. **Mindy**: \( 5.5 \)
3. **Bob**: \( 5.5 \)
4. **Aron**: \( 5.75 \)
So, from least to greatest, the order of distances is:
**Tuna, Mindy, Bob, Aron.**
1. **Mindy**: \(5.5\) is already in decimal form.
2. **Aron**: \( \frac{23}{4} = 5.75 \)
3. **Tuna**: \( \sqrt{28} \) can be approximated as follows:
- \( \sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7} \approx 2 \times 2.64575 \approx 5.2915 \)
4. **Bob**: \( 5 \frac{1}{2} = 5.5 \) in decimal form.
Now, let's list the distances:
- Mindy: \(5.5\)
- Aron: \(5.75\)
- Tuna: \(5.2915\)
- Bob: \(5.5\)
Now we can order the distances from least to greatest:
1. **Tuna**: \( \sqrt{28} \approx 5.2915 \)
2. **Mindy**: \( 5.5 \)
3. **Bob**: \( 5.5 \)
4. **Aron**: \( 5.75 \)
So, from least to greatest, the order of distances is:
**Tuna, Mindy, Bob, Aron.**
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