Question
Four people have found the distance in kilometers across a small bridge using different methods.Their results are given in the table. Order the distances from least to greatest.
Mindy lAron l Tuna l Bob
5.5¯ l 23/4l √28 l 5 1/2l
5.5¯ l
Mindy lAron l Tuna l Bob
5.5¯ l 23/4l √28 l 5 1/2l
5.5¯ l
Answers
Answered by
GPT-4o mini
To order the distances from least to greatest, let's first convert all the values into a numerical format.
1. **Mindy**: \( 5.5 \overline{(5)} \) is the same as \( 5.555... \), which is a repeating decimal.
2. **Aron**: \( \frac{23}{4} \) can be converted to a decimal:
\[
\frac{23}{4} = 5.75
\]
3. **Tuna**: \( \sqrt{28} \):
\[
\sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7} \approx 2 \times 2.64575 \approx 5.2915
\]
4. **Bob**: \( 5 \frac{1}{2} \) can be converted to a decimal:
\[
5 \frac{1}{2} = 5.5
\]
Now we have the following distances:
- Mindy: \( 5.555... \)
- Aron: \( 5.75 \)
- Tuna: \( 5.2915 \)
- Bob: \( 5.5 \)
Now, let's order these from least to greatest:
1. Tuna: \( 5.2915 \)
2. Bob: \( 5.5 \)
3. Mindy: \( 5.555... \)
4. Aron: \( 5.75 \)
So the order from least to greatest is:
**Tuna < Bob < Mindy < Aron**
1. **Mindy**: \( 5.5 \overline{(5)} \) is the same as \( 5.555... \), which is a repeating decimal.
2. **Aron**: \( \frac{23}{4} \) can be converted to a decimal:
\[
\frac{23}{4} = 5.75
\]
3. **Tuna**: \( \sqrt{28} \):
\[
\sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7} \approx 2 \times 2.64575 \approx 5.2915
\]
4. **Bob**: \( 5 \frac{1}{2} \) can be converted to a decimal:
\[
5 \frac{1}{2} = 5.5
\]
Now we have the following distances:
- Mindy: \( 5.555... \)
- Aron: \( 5.75 \)
- Tuna: \( 5.2915 \)
- Bob: \( 5.5 \)
Now, let's order these from least to greatest:
1. Tuna: \( 5.2915 \)
2. Bob: \( 5.5 \)
3. Mindy: \( 5.555... \)
4. Aron: \( 5.75 \)
So the order from least to greatest is:
**Tuna < Bob < Mindy < Aron**
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