To determine which functions decrease at a rate of 40% per unit increase in \( x \), we need to look for exponential functions of the form:
\[ f(x) = A \cdot b^x \]
where the base \( b \) must be less than 1 because we want a decreasing function. A rate of decrease of 40% means that for every unit increase in \( x \), the function value should be multiplied by \( 1 - 0.4 = 0.6 \). Thus, we want:
\[ b = 0.6 \]
Now, let's evaluate each option to see if the base matches 0.6:
A. \( f(x) = \frac{3}{2} \left(\frac{2}{5}\right)^x \)
- Base: \( \frac{2}{5} = 0.4 \) (decreasing but not at 40%)
B. \( f(x) = \frac{2}{3} \left(\frac{3}{5}\right)^x \)
- Base: \( \frac{3}{5} = 0.6 \) (decreases at 40%)
C. \( f(x) = \frac{2}{5} \left(\frac{5}{8}\right)^x \)
- Base: \( \frac{5}{8} = 0.625 \) (decreasing but not at 40%)
D. \( f(x) = 1.75 (0.6)^x \)
- Base: \( 0.6 \) (decreases at 40%)
E. \( f(x) = 2.5 (0.4)^x \)
- Base: \( 0.4 \) (decreasing but not at 40%)
F. \( f(x) = 0.4 (0.8)^x \)
- Base: \( 0.8 \) (decreasing but not at 40%)
The functions that decrease at a rate of 40% per unit increase in \( x \) are:
B. \( f(x) = \frac{2}{3} \left(\frac{3}{5}\right)^x \)
D. \( f(x) = 1.75 (0.6)^x \)
So the final answer is B and D.