To determine the intervals where the function \( g(x) \) is growing at a faster rate than \( f(x) \), we can compare the outputs of both functions at the given \( x \) values.
Values from the Functions:
-
For \( f(x) = 8x^3 \):
- \( f(0) = 0 \)
- \( f(0.25) = 0.125 \)
- \( f(0.5) = 1 \)
- \( f(1) = 8 \)
- \( f(2) = 64 \)
- \( f(3) = 216 \)
- \( f(4) = 512 \)
- \( f(5) = 1000 \)
- \( f(10) = 8000 \)
- \( f(15) = 27000 \)
- \( f(20) = 64000 \)
-
For \( g(x) = 2^x \):
- \( g(0) = 1 \)
- \( g(0.25) = 1.19 \)
- \( g(0.5) = 1.41 \)
- \( g(1) = 2 \)
- \( g(2) = 4 \)
- \( g(3) = 8 \)
- \( g(4) = 16 \)
- \( g(5) = 32 \)
- \( g(10) = 1024 \)
- \( g(15) = 32768 \)
- \( g(20) = 1048576 \)
Comparing Growth Rates in Each Interval:
-
Interval 0 to 0.25:
- \( f(0) = 0 \), \( f(0.25) = 0.125 \)
- \( g(0) = 1 \), \( g(0.25) = 1.19 \)
- \( g(x) > f(x) \): True
-
Interval 0 to 0.5:
- \( f(0.5) = 1 \)
- \( g(0.5) = 1.41 \)
- \( g(x) > f(x) \): True
-
Interval 0 to 20:
- As shown, \( g(x) > f(x) \) from \( 0 \) to \( 20 \): True
-
Interval 1 to 10:
- \( f(1) = 8 \), \( g(1) = 2 \)
- \( g(2) = 4 \), \( f(2) = 64 \)
- \( f(3) = 216 \), \( g(3) = 8 \)
- \( f(4) = 512 \), \( g(4) = 16 \)
- \( f(5) = 1000 \), \( g(5) = 32 \)
- At \( x = 1, 2, 3, 4, 5 \): \( f(x) > g(x) \): False
-
Interval 15 to 20:
- \( f(15) = 27000 \), \( g(15) = 32768 \)
- \( f(20) = 64000 \), \( g(20) = 1048576 \)
- \( g(x) > f(x) \) at first but then grows significantly faster at \( g(20) >> f(20) \): True
Conclusion:
The intervals where \( g(x) \) grows at a faster rate than \( f(x) \) are:
Correct options:
- A. 0 to 0.25
- B. 0 to 0.5
- C. 0 to 20
- E. 15 to 20
Thus, the answer options are A, B, C, and E.