How many of the following equations have the solution set {5} ? 2(x−3)+1=5 3b15=1 2h−30=40 (1 point)

To determine how many of the given equations have the solution set {5}, we will solve each equation and check if \(x = 5\), \(b = 5\), or \(h = 5\) is the only solution.

1. **For the equation \(2(x - 3) + 1 = 5\):**
\[
2(x - 3) + 1 = 5
\]
First, simplify:
\[
2x - 6 + 1 = 5
\]
\[
2x - 5 = 5
\]
Add 5 to both sides:
\[
2x = 10
\]
Divide by 2:
\[
x = 5
\]
The solution is \(x = 5\).

2. **For the equation \(3b + 15 = 1\):**
\[
3b + 15 = 1
\]
Subtract 15 from both sides:
\[
3b = 1 - 15
\]
\[
3b = -14
\]
Divide by 3:
\[
b = -\frac{14}{3}
\]
The solution is not \(b = 5\).

3. **For the equation \(2h - 30 = 40\):**
\[
2h - 30 = 40
\]
Add 30 to both sides:
\[
2h = 40 + 30
\]
\[
2h = 70
\]
Divide by 2:
\[
h = 35
\]
The solution is not \(h = 5\).

In summary, only the first equation \(2(x - 3) + 1 = 5\) has the solution set \{5\}. Therefore, the total number of equations that have the solution set \{5\} is:

\[
\boxed{1}
\]