To solve the equation \(x^2 + 6x + 5 = 0\) by completing the square, let's fill in the blanks step by step:
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Start with the equation: \[ x^2 + 6x + 5 = 0 \]
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Rearrange it: \[ x^2 + 6x + _ = -5 + _ \] Here, you need to complete the square.
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To complete the square, you take half of the coefficient of \(x\), which is \(6\), and square it:
- Half of 6 is \(3\), and squaring it gives \(9\).
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Now, fill in the blanks:
- Blank space 1: 9
- Blank space 2: 9
The equation now looks like: \[ x^2 + 6x + 9 = -5 + 9 \]
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This simplifies to: \[ (x + 3)^2 = 4 \]
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Now, we can identify:
- Blank space 3: 3
- Blank space 4: 4
The equation is now: \[ (x + 3)^2 = 4 \]
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Next, take the square root of both sides: \[ x + 3 = \pm 2 \]
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The next steps involve isolating \(x\): \[ x = -3 \pm 2 \]
This gives us two separate equations:
- \(x = -3 + 2\) which is \(x = -1\)
- \(x = -3 - 2\) which is \(x = -5\)
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Finally, we can fill in:
- Blank space 5: 3
- Blank space 6: 2
- Blank space 7: -1
- Blank space 8: -5
In summary, here are all the filled in values:
- Blank space 1: 9
- Blank space 2: 9
- Blank space 3: 3
- Blank space 4: 4
- Blank space 5: 3
- Blank space 6: 2
- Blank space 7: -1
- Blank space 8: -5