Asked by eeeeee
Which expression is equal to 8?
Answer options with 5 options
A.
left-parenthesis 2 Superscript StartFraction 1 over 4 EndFraction Baseline right-parenthesis Superscript 4 Baseline
B.
left-parenthesis 4 Superscript StartFraction 1 over 2 EndFraction Baseline right-parenthesis Superscript 2 Baseline
C.
left-parenthesis 6 Superscript StartFraction 1 over 3 EndFraction Baseline right-parenthesis Superscript 3 Baseline
D.
left-parenthesis 8 Superscript StartFraction 1 over 2 EndFraction Baseline right-parenthesis Superscript 2 Baseline
E.
left-parenthesis 16 Superscript StartFraction 1 over 4 EndFraction Baseline right-parenthesis Superscript 4 Baseline
Answer options with 5 options
A.
left-parenthesis 2 Superscript StartFraction 1 over 4 EndFraction Baseline right-parenthesis Superscript 4 Baseline
B.
left-parenthesis 4 Superscript StartFraction 1 over 2 EndFraction Baseline right-parenthesis Superscript 2 Baseline
C.
left-parenthesis 6 Superscript StartFraction 1 over 3 EndFraction Baseline right-parenthesis Superscript 3 Baseline
D.
left-parenthesis 8 Superscript StartFraction 1 over 2 EndFraction Baseline right-parenthesis Superscript 2 Baseline
E.
left-parenthesis 16 Superscript StartFraction 1 over 4 EndFraction Baseline right-parenthesis Superscript 4 Baseline
Answers
Answered by
GPT-4o mini
To determine which expression equals 8, let's evaluate each option:
**A. \((2^{\frac{1}{4}})^4\)**
Using the power of a power property \((a^m)^n = a^{m \cdot n}\):
\[
(2^{\frac{1}{4}})^4 = 2^{\frac{1}{4} \cdot 4} = 2^1 = 2
\]
**B. \((4^{\frac{1}{2}})^2\)**
\[
(4^{\frac{1}{2}})^2 = 4^{\frac{1}{2} \cdot 2} = 4^1 = 4
\]
**C. \((6^{\frac{1}{3}})^3\)**
\[
(6^{\frac{1}{3}})^3 = 6^{\frac{1}{3} \cdot 3} = 6^1 = 6
\]
**D. \((8^{\frac{1}{2}})^2\)**
\[
(8^{\frac{1}{2}})^2 = 8^{\frac{1}{2} \cdot 2} = 8^1 = 8
\]
**E. \((16^{\frac{1}{4}})^4\)**
\[
(16^{\frac{1}{4}})^4 = 16^{\frac{1}{4} \cdot 4} = 16^1 = 16
\]
From the evaluations above, the expression that equals 8 is:
**D. \((8^{\frac{1}{2}})^2\)**
**A. \((2^{\frac{1}{4}})^4\)**
Using the power of a power property \((a^m)^n = a^{m \cdot n}\):
\[
(2^{\frac{1}{4}})^4 = 2^{\frac{1}{4} \cdot 4} = 2^1 = 2
\]
**B. \((4^{\frac{1}{2}})^2\)**
\[
(4^{\frac{1}{2}})^2 = 4^{\frac{1}{2} \cdot 2} = 4^1 = 4
\]
**C. \((6^{\frac{1}{3}})^3\)**
\[
(6^{\frac{1}{3}})^3 = 6^{\frac{1}{3} \cdot 3} = 6^1 = 6
\]
**D. \((8^{\frac{1}{2}})^2\)**
\[
(8^{\frac{1}{2}})^2 = 8^{\frac{1}{2} \cdot 2} = 8^1 = 8
\]
**E. \((16^{\frac{1}{4}})^4\)**
\[
(16^{\frac{1}{4}})^4 = 16^{\frac{1}{4} \cdot 4} = 16^1 = 16
\]
From the evaluations above, the expression that equals 8 is:
**D. \((8^{\frac{1}{2}})^2\)**
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