Asked by treybot
A diver searches for a sunken treasure that is 97.2
feet below the surface. What is the diver's elevation when he is 2/3 of the way down? (1 point)
Responses
−64.8
ft.
negative 64 point 8 ft.
−32.4
ft.
negative 32 point 4 ft.
−145.8 ft.
negative 145 point 8 ft.
−48.5
ft.
negative 48 point 5 ft.
feet below the surface. What is the diver's elevation when he is 2/3 of the way down? (1 point)
Responses
−64.8
ft.
negative 64 point 8 ft.
−32.4
ft.
negative 32 point 4 ft.
−145.8 ft.
negative 145 point 8 ft.
−48.5
ft.
negative 48 point 5 ft.
Answers
Answered by
GPT-4o mini
To find the diver's elevation when he is \( \frac{2}{3} \) of the way down to the treasure, we first calculate the depth of that point.
The total depth of the treasure is \( 97.2 \) feet. To find \( \frac{2}{3} \) of that depth, we calculate:
\[
\text{Depth at } \frac{2}{3} = \frac{2}{3} \times 97.2
\]
Calculating that gives:
\[
\frac{2}{3} \times 97.2 = 64.8
\]
This means the diver has descended \( 64.8 \) feet down. Since below the surface is represented as a negative elevation, the diver's elevation when he is \( \frac{2}{3} \) of the way down is:
\[
-64.8 \text{ feet}
\]
Thus, the correct response is:
**−64.8 ft.** (negative 64 point 8 ft.)
The total depth of the treasure is \( 97.2 \) feet. To find \( \frac{2}{3} \) of that depth, we calculate:
\[
\text{Depth at } \frac{2}{3} = \frac{2}{3} \times 97.2
\]
Calculating that gives:
\[
\frac{2}{3} \times 97.2 = 64.8
\]
This means the diver has descended \( 64.8 \) feet down. Since below the surface is represented as a negative elevation, the diver's elevation when he is \( \frac{2}{3} \) of the way down is:
\[
-64.8 \text{ feet}
\]
Thus, the correct response is:
**−64.8 ft.** (negative 64 point 8 ft.)
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