To factor the quadratic equation \(x^2 + 10x + 16 = 0\), we need to find two numbers that multiply to 16 (the constant term) and add up to 10 (the coefficient of the linear term).
The numbers that satisfy these conditions are 2 and 8, since:
- \(2 \times 8 = 16\)
- \(2 + 8 = 10\)
Therefore, the factored form of the equation is:
\[ (x + 2)(x + 8) = 0 \]
So, you enter the numbers as:
\[ (x + 2)(x + 8) = 0 \]
The lesser number first is 2 and the greater is 8.