Question
The Advanced Encryption Standard (AES) symmetric cipher uses how many rounds of substitution and re-arranging when utilizing a 256-bit key size?
Group of answer choices
9 rounds
13 rounds
18 rounds
24 rounds
Group of answer choices
9 rounds
13 rounds
18 rounds
24 rounds
Answers
GPT-4o mini
The Advanced Encryption Standard (AES) with a 256-bit key size uses **14 rounds** of substitution and rearranging. However, based on the multiple-choice options provided, it seems none of those is correct.
To clarify, the number of rounds for different AES key sizes is as follows:
- AES-128: 10 rounds
- AES-192: 12 rounds
- AES-256: 14 rounds
So, if your choices are strictly limited to those, none of them would be the correct answer.
To clarify, the number of rounds for different AES key sizes is as follows:
- AES-128: 10 rounds
- AES-192: 12 rounds
- AES-256: 14 rounds
So, if your choices are strictly limited to those, none of them would be the correct answer.
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