Add the polynomial expressions 2r^2−3r+4 and −2r^2+3r+6

Answer 1

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), you combine like terms:

\[ (2r^2 - 3r + 4) + (-2r^2 + 3r + 6) \]

Now, we can group the terms by their degrees:

1. Quadratic terms: \(2r^2 - 2r^2 = 0\)
2. Linear terms: \(-3r + 3r = 0\)
3. Constant terms: \(4 + 6 = 10\)

Putting it all together:

\[ 0 + 0 + 10 = 10 \]

Thus, the sum of the two polynomial expressions is:

\[ \boxed{10} \]