Question

Solve the following word problem. The air temperature at 9 a.m. is −5.8
degrees Celsius. The air temperature at noon is −1.6
degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.

Answer 1

Make it sound like a 5th grader and not a robot, Make it on sentence

Answer 2

To find the change in temperature, we can set up the equation based on the initial temperature and the final temperature.

Let \( T_1 \) be the temperature at 9 a.m. and \( T_2 \) be the temperature at noon.

- \( T_1 = -5.8 \) degrees Celsius
- \( T_2 = -1.6 \) degrees Celsius

The change in temperature (\( \Delta T \)) can be calculated using the equation:

\[
\Delta T = T_2 - T_1
\]

Substituting in the values:

\[
\Delta T = (-1.6) - (-5.8)
\]

This simplifies to:

\[
\Delta T = -1.6 + 5.8
\]
\[
\Delta T = 4.2
\]

The change in temperature during these three hours is \( 4.2 \) degrees Celsius.

### Explanation of the Answer:
This change in temperature means that the air temperature increased by \( 4.2 \) degrees Celsius from 9 a.m. to noon. Initially, the temperature was very cold at \( -5.8 \) degrees Celsius, and it warmed up to \( -1.6 \) degrees Celsius. Thus, the temperature became significantly warmer over the three-hour period.

Answer 3

The temperature went up by 4.2 degrees Celsius from -5.8 degrees at 9 a.m. to -1.6 degrees at noon, which means it got warmer outside!