Question

Is pi greater than or less than square root of 8

Answer 1

To compare \(\pi\) and \(\sqrt{8}\), we can first calculate \(\sqrt{8}\).

\[
\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2}
\]

Now, we can approximate \(\sqrt{2}\). The value of \(\sqrt{2}\) is approximately 1.414, so:

\[
\sqrt{8} = 2 \times 1.414 \approx 2.828
\]

The value of \(\pi\) is approximately 3.14159.

Now we can compare the two values:

\[
\pi \approx 3.14159 \quad \text{and} \quad \sqrt{8} \approx 2.828
\]

Since \(3.14159 > 2.828\), we conclude that:

\[
\pi > \sqrt{8}
\]