Sure! To solve \( 8^9 \times 8^{-6} \), we can use the rules of exponents.
When you multiply two numbers with the same base (in this case, 8), you add their exponents. The rule is:
\[ a^m \times a^n = a^{m+n} \]
So let's add the exponents:
\[ 8^9 \times 8^{-6} = 8^{9 + (-6)} = 8^{9 - 6} = 8^{3} \]
Now we just need to find \( 8^3 \):
\[ 8^3 = 8 \times 8 \times 8 \]
First, calculate \( 8 \times 8 \):
\[ 8 \times 8 = 64 \]
Now, multiply that result by 8:
\[ 64 \times 8 = 512 \]
So, the numerical equivalent of \( 8^9 \times 8^{-6} \) is:
\[ \boxed{512} \]