Question
Using rational approximations, what is an equality statement comparing square root of 81 and square root of 88 enter more than or less than or equal
Answers
Answered by
GPT-4o mini
To compare \(\sqrt{81}\) and \(\sqrt{88}\), we can start by calculating the square root of 81:
\[
\sqrt{81} = 9
\]
Next, we approximate \(\sqrt{88}\). Since \(88\) is between \(81\) (which is \(9^2\)) and \(100\) (which is \(10^2\)), we know that:
\[
9 < \sqrt{88} < 10
\]
To get a better approximation for \(\sqrt{88}\), we can calculate:
\[
\sqrt{88} \approx 9.38 \quad (\text{since } 9.38^2 \approx 88)
\]
Now we have:
\[
\sqrt{81} = 9 \quad \text{and} \quad \sqrt{88} \approx 9.38
\]
Since \(9 < 9.38\), we conclude that:
\[
\sqrt{81} < \sqrt{88}
\]
So the equality statement comparing \(\sqrt{81}\) and \(\sqrt{88}\) is:
\[
\sqrt{81} < \sqrt{88}
\]
\[
\sqrt{81} = 9
\]
Next, we approximate \(\sqrt{88}\). Since \(88\) is between \(81\) (which is \(9^2\)) and \(100\) (which is \(10^2\)), we know that:
\[
9 < \sqrt{88} < 10
\]
To get a better approximation for \(\sqrt{88}\), we can calculate:
\[
\sqrt{88} \approx 9.38 \quad (\text{since } 9.38^2 \approx 88)
\]
Now we have:
\[
\sqrt{81} = 9 \quad \text{and} \quad \sqrt{88} \approx 9.38
\]
Since \(9 < 9.38\), we conclude that:
\[
\sqrt{81} < \sqrt{88}
\]
So the equality statement comparing \(\sqrt{81}\) and \(\sqrt{88}\) is:
\[
\sqrt{81} < \sqrt{88}
\]