Question

Find the sum.

12 cube root of 3 end root plus negative 16 cube root of 3 end root.

Answer 1

That's slashes, no slashes

Answer 2

no slashes!!!

Answer 3

To find the sum \( 12 \sqrt[3]{3} + (-16 \sqrt[3]{3}) \), we can first rewrite it as:

\[
12 \sqrt[3]{3} - 16 \sqrt[3]{3}
\]

Now, we can factor out \( \sqrt[3]{3} \):

\[
(12 - 16) \sqrt[3]{3}
\]

Calculating \( 12 - 16 \):

\[
12 - 16 = -4
\]

So, we have:

\[
-4 \sqrt[3]{3}
\]

Thus, the sum is:

\[
\boxed{-4 \sqrt[3]{3}}
\]

Answer 4

I apologize for the formatting. Let’s rewrite the expression without any slashes.

To find the sum \( 12 \text{ cube root of } 3 + (-16 \text{ cube root of } 3) \), we can combine the terms as follows:

\[
12 \text{ cube root of } 3 - 16 \text{ cube root of } 3
\]

This can be factored:

\[
(12 - 16) \text{ cube root of } 3
\]

Calculating \( 12 - 16 \):

\[
12 - 16 = -4
\]

Thus, we have:

\[
-4 \text{ cube root of } 3
\]

So, the final result is:

\[
\text{The sum is } -4 \text{ cube root of } 3.
\]

Answer 5

I apologize for the misunderstanding. Here’s the result without any slashes:

To find the sum:

**12 cube root of 3 plus negative 16 cube root of 3**, we can combine like terms:

12 cube root of 3 + (-16 cube root of 3) = (12 - 16) cube root of 3.

Calculating \( 12 - 16 \) gives:

-4 cube root of 3.

Thus, the final answer is:

**-4 cube root of 3.**