Asked by cloudicus
Which of the following correctly demonstrates the use of the Commutative Property of Multiplication?(1 point)
Responses
2(b10+z11)=(b10+z11)⋅2
11(b+z)=11b+11z
z11⋅2=z11+2
3(b10+4)=3(4+b10)3
Responses
2(b10+z11)=(b10+z11)⋅2
11(b+z)=11b+11z
z11⋅2=z11+2
3(b10+4)=3(4+b10)3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
The option that correctly demonstrates the use of the Commutative Property of Multiplication is:
**11(b+z)=11b+11z**
This expression showcases the distributive property rather than the commutative property. To correctly demonstrate the commutative property of multiplication, you would show that changing the order of multiplication doesn't change the result, such as:
**2 * 3 = 3 * 2**
However, neither of the options correctly illustrates the commutative property as they involve distribution or addition rather than simply rearranging multiplicands.
If you need an example using the commutative property with multiplication, you could consider something like:
**a * b = b * a**
If you would like to recheck the definitions or examples, please feel free to ask!
**11(b+z)=11b+11z**
This expression showcases the distributive property rather than the commutative property. To correctly demonstrate the commutative property of multiplication, you would show that changing the order of multiplication doesn't change the result, such as:
**2 * 3 = 3 * 2**
However, neither of the options correctly illustrates the commutative property as they involve distribution or addition rather than simply rearranging multiplicands.
If you need an example using the commutative property with multiplication, you could consider something like:
**a * b = b * a**
If you would like to recheck the definitions or examples, please feel free to ask!
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