To simplify the expression \(\sqrt{28} + 3\sqrt{63}\), we can follow the steps in order:
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Start with the original expression: \(\sqrt{28} + 3\sqrt{63}\)
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Factor the square roots: \(\sqrt{28} = \sqrt{4 \cdot 7} = 2\sqrt{7}\) and \(\sqrt{63} = \sqrt{9 \cdot 7} = 3\sqrt{7}\)
- Now the expression becomes: \(2\sqrt{7} + 3(3\sqrt{7})\)
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Combine the terms: Substitute \(\sqrt{63}\) into the expression:
- \(2\sqrt{7} + 3 \cdot 3\sqrt{7}\) which simplifies to: \(2\sqrt{7} + 9\sqrt{7}\)
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Combine like terms: \(11\sqrt{7}\)
So the correct order is:
- Start with \(\sqrt{28} + 3\sqrt{63}\)
- Factor into \(\sqrt{4 \cdot 7}\) and \(\sqrt{9 \cdot 7}\)
- Combine to \(2\sqrt{7} + 9\sqrt{7}\)
- Final result is \(11\sqrt{7}\)
Thus, the sequence is:
- = \(\sqrt{28} + 3\sqrt{63}\)
- = \(2\sqrt{7} + 9\sqrt{7}\)
- = \(11\sqrt{7}\)
None of the expressions you provided match the correct simplified results and steps. The simplification is not presented correctly in your options, but the correct final answer is indeed \(11\sqrt{7}\).