Question
Using a number line, what is the approximate value of 19−−√ ?(1 point)
Responses
4.38
4.38
4.25
4.25
4.5
4.5
4.13
4.13
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Responses
4.38
4.38
4.25
4.25
4.5
4.5
4.13
4.13
Skip to navigation
Answers
Answer
Using a number line, what whole number and rational number to the nearest half is 105−−−√ between?(1 point)
Responses
between 10 and 10.5
between 10 and 10.5
between 9.5 and 10
between 9.5 and 10
between 10.5 and 11
between 10.5 and 11
between 11 and 11.5
Responses
between 10 and 10.5
between 10 and 10.5
between 9.5 and 10
between 9.5 and 10
between 10.5 and 11
between 10.5 and 11
between 11 and 11.5
Answered by
GPT-4o mini
To find the approximate value of \(\sqrt{19}\), we can consider perfect squares that are close to 19. The perfect squares are:
- \(4^2 = 16\)
- \(5^2 = 25\)
Since \(16 < 19 < 25\), we know that \(4 < \sqrt{19} < 5\).
To refine our estimate, we can check values between 4 and 5:
- \(4.4^2 = 19.36\) (too high)
- \(4.3^2 = 18.49\) (too low)
So, \(\sqrt{19}\) is between 4.3 and 4.4.
Let's check \(4.35\):
- \(4.35^2 = 18.9225\) (still too low)
Now, let's check \(4.36\):
- \(4.36^2 = 19.0496\) (too high)
Then we check \(4.34\):
- \(4.34^2 = 18.8356\) (too low)
After some calculations, we can conclude that \(\sqrt{19}\) is approximately \(4.36\), which is close to \(4.38\).
So the closest answer from your options would be:
**4.38**.
- \(4^2 = 16\)
- \(5^2 = 25\)
Since \(16 < 19 < 25\), we know that \(4 < \sqrt{19} < 5\).
To refine our estimate, we can check values between 4 and 5:
- \(4.4^2 = 19.36\) (too high)
- \(4.3^2 = 18.49\) (too low)
So, \(\sqrt{19}\) is between 4.3 and 4.4.
Let's check \(4.35\):
- \(4.35^2 = 18.9225\) (still too low)
Now, let's check \(4.36\):
- \(4.36^2 = 19.0496\) (too high)
Then we check \(4.34\):
- \(4.34^2 = 18.8356\) (too low)
After some calculations, we can conclude that \(\sqrt{19}\) is approximately \(4.36\), which is close to \(4.38\).
So the closest answer from your options would be:
**4.38**.
Answered by
GPT-4o mini
To determine the value of \(\sqrt{105}\) and its position on a number line, we can examine the perfect squares:
- \(10^2 = 100\)
- \(11^2 = 121\)
Since \(100 < 105 < 121\), we can conclude that:
\[
10 < \sqrt{105} < 11
\]
Next, we can refine the estimate of \(\sqrt{105}\) by checking values between 10 and 11:
- \(10.2^2 = 104.04\) (too low)
- \(10.3^2 = 106.09\) (too high)
This shows \(\sqrt{105}\) is between \(10.2\) and \(10.3\).
Now, let's round to the nearest half:
- The nearest halves around \(10.2\) and \(10.3\) are \(10\) and \(10.5\).
Thus, we can conclude that:
\(\sqrt{105}\) is between **10 and 10.5**.
- \(10^2 = 100\)
- \(11^2 = 121\)
Since \(100 < 105 < 121\), we can conclude that:
\[
10 < \sqrt{105} < 11
\]
Next, we can refine the estimate of \(\sqrt{105}\) by checking values between 10 and 11:
- \(10.2^2 = 104.04\) (too low)
- \(10.3^2 = 106.09\) (too high)
This shows \(\sqrt{105}\) is between \(10.2\) and \(10.3\).
Now, let's round to the nearest half:
- The nearest halves around \(10.2\) and \(10.3\) are \(10\) and \(10.5\).
Thus, we can conclude that:
\(\sqrt{105}\) is between **10 and 10.5**.
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