To find the formula for the \(n\)-th term \(a_n\) of the given arithmetic sequence, we first need to identify the common difference and the first term of the sequence.
We have the terms:
- \(a_2 = 13\)
- \(a_4 = 25\)
- \(a_6 = 37\)
- \(a_8 = 49\)
Let's calculate the common difference \(d\) using the first two terms we have:
- \(a_4 - a_2 = 25 - 13 = 12\)
- Since \(a_4\) is the 4th term and \(a_2\) is the 2nd term, two terms apart indicates that the difference will be \(d \cdot 2 = 12\). Hence, \(d = 12/2 = 6\).
Now that we have the common difference \(d = 6\), we can determine a formula for the \(n\)-th term. The general formula for an arithmetic sequence is:
\[ a_n = a_1 + (n-1)d \]
We already know \(d = 6\). We need to find \(a_1\), the first term of the sequence.
We can find \(a_1\) by using \(a_2\): \[ a_2 = a_1 + (2-1)d \implies 13 = a_1 + 1 \cdot 6 \implies a_1 + 6 = 13 \implies a_1 = 7 \]
Now we can substitute \(a_1\) and \(d\) into the formula:
\[ a_n = 7 + (n-1)6 \]
Now simplifying this gives:
\[ a_n = 7 + 6(n-1) \implies a_n = 7 + 6n - 6 \implies a_n = 6n + 1 \]
So the formula to find \(a_n\) is:
\[ a_n = 7 + 6(n - 1) \]
Looking at the provided options, we see that option D matches our derived formula.
The correct answer is:
D. \(a_n = 7 + 6(n - 1)\)