Question

Triangle ABC is reflected across the x -axis. If the coordinates of the original shape are A(−4,−1) , B(−5,−2) , and C(−10,−1) , what are the coordinates of A′ , B′ , and C′ ?(1 point) Responses A′(4,−1), B′(5,−2), and C′(10,−1) upper A prime left parenthesis 4 comma negative 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis 10 comma negative 1 right parenthesis A′(−4,1), B′(5,−2), and C′(−10,1) upper A prime left parenthesis negative 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma negative 2 right parenthesis , and upper C prime left parenthesis negative 10 comma 1 right parenthesis A′(4,1), B′(5,2), and C′(10,1) upper A prime left parenthesis 4 comma 1 right parenthesis , upper B prime left parenthesis 5 comma 2 right parenthesis , and upper C prime left parenthesis 10 comma 1 right parenthesis A′(−4,1), B′(−5,2), and C′(−10,1)

Answer 1

When a point \((x, y)\) is reflected across the x-axis, the new coordinates become \((x, -y)\).

Let's apply this to each of the points:

1. For point A \((-4, -1)\):
\[
A' = (-4, -(-1)) = (-4, 1)
\]

2. For point B \((-5, -2)\):
\[
B' = (-5, -(-2)) = (-5, 2)
\]

3. For point C \((-10, -1)\):
\[
C' = (-10, -(-1)) = (-10, 1)
\]

So the coordinates of the reflected points are:
- \(A'(-4, 1)\)
- \(B'(-5, 2)\)
- \(C'(-10, 1)\)

Thus, the correct response is:
**A′(−4,1), B′(−5,2), and C′(−10,1)**.