Question

Which number is a factor of the prime factorization of 60

Answer 1

To find a factor of the prime factorization of 60, we first need to determine the prime factorization itself.

The prime factorization of 60 is:
\[ 60 = 2^2 \times 3^1 \times 5^1 \]

From this factorization, we can see that the factors of 60 include:
- \( 1 \) (since every number is divisible by 1)
- \( 2 \)
- \( 3 \)
- \( 4 \) (which is \( 2^2 \))
- \( 5 \)
- \( 6 \) (which is \( 2 \times 3 \))
- \( 10 \) (which is \( 2 \times 5 \))
- \( 12 \) (which is \( 3 \times 4 \))
- \( 15 \) (which is \( 3 \times 5 \))
- \( 20 \) (which is \( 4 \times 5 \))
- \( 30 \) (which is \( 2 \times 3 \times 5 \))
- \( 60 \) itself

Any of the prime factors (2, 3, 5) or their products (like 4, 6, etc.) can be considered factors of the prime factorization of 60.

So, any of these numbers could be a valid answer. For instance, \( 2 \) is a factor involved in the prime factorization of \( 60 \).