Question

Is √12 greater then π

Answer 1

To determine whether \(\sqrt{12}\) is greater than \(\pi\), we first need to evaluate \(\sqrt{12}\).

\[
\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3}
\]

Now we can estimate \(\sqrt{3}\). The value of \(\sqrt{3}\) is approximately \(1.732\), so:

\[
2\sqrt{3} \approx 2 \times 1.732 \approx 3.464
\]

Next, we know the approximate value of \(\pi\):

\[
\pi \approx 3.14159
\]

Now we can compare the two values:

\[
\sqrt{12} \approx 3.464 \quad \text{and} \quad \pi \approx 3.14159
\]

Since \(3.464 > 3.14159\), we can conclude that:

\[
\sqrt{12} > \pi
\]

Thus, \(\sqrt{12}\) is greater than \(\pi\).