use the function rules to find the coordinates of triangle A", B", C" and predict the quadrant it will be in after the transformations. triangleABC, with coordinates A(-8,4), B(-5,8), and C(-3,3), is transformed be (x,y) arrow (x+4, y-6) to produce triangleA'B'C'. triangleA', B', C' is transformed by the rule (x,y) arrow (x+5, y-3). Create the rule for the composition transformation and predict what quadrant the image will be in

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2 months ago

To find the coordinates of the transformed triangle \( A''B''C'' \) and determine in which quadrant it will lie, we need to apply the transformations step-by-step.

### Step 1: First Transformation

The first transformation is given by the rule:

\[
(x, y) \rightarrow (x + 4, y - 6)
\]

Let's apply this transformation to each vertex of triangle \( ABC \):

1. **Point :
\[
A(-8, 4) \rightarrow (-8 + 4, 4 - 6) = (-4, -2)
\]

2. **Point B**:
\[
B(-5, 8) \rightarrow (-5 + 4, 8 - 6) = (-1, 2)
\]

3. **Point C**:
\[
C(-3, 3) \rightarrow (-3 + 4, 3 - 6) = (1, -3)
\]

So, after the first transformation, the coordinates of triangle \( A'B'C' \) are:
- \( A'(-4, -2) \)
- \( B'(-1, 2) \)
- \( C'(1, -3) \)

### Step 2: Second Transformation

The second transformation is defined by the rule:

\[
(x, y) \rightarrow (x + 5, y - 3)
\]

Now, we apply this transformation to each point of triangle \( A'B'C' \):

1. **Point A'**:
\[
A'(-4, -2) \rightarrow (-4 + 5, -2 - 3) = (1, -5)
\]

2. **Point B'**:
\[
B'(-1, 2) \rightarrow (-1 + 5, 2 - 3) = (4, -1)
\]

3. **Point C'**:
\[
C'(1, -3) \rightarrow (1 + 5, -3 - 3) = (6, -6)
\]

So, after the second transformation, the coordinates of triangle \( A''B''C'' \) are:
- \( A''(1, -5) \)
- \( B''(4, -1) \)
- \( C''(6, -6) \)

### Step 3: Predicting the Quadrant

Now, we need to determine the quadrant where triangle \( A''B''C'' \) is located.

1. **Point A''(1, -5)**: \( x > 0 \) and \( y < 0 \) (Quadrant IV)
2. **Point B''(4, -1)**: \( x > 0 \) and \( y < 0 \) (Quadrant IV)
3. **Point C''(6, -6)**: \( x > 0 \) and \( y < 0 \) (Quadrant IV)

All three points are in Quadrant IV.

### Conclusion

The coordinates of triangle \( A''B''C'' \) are:
- \( A''(1, -5) \)
- \( B''(4, -1) \)
- \( C''(6, -6) \)

After the transformations, triangle \( A''B''C'' \) will be located entirely in **Quadrant IV**.